Key points about enlargement

An enlargementA transformation of a shape which results in a shape increasing or decreasing in size. is one of the four types of transformationA transformation changes the position or size of a shape..
An enlargement increases or decreases the size of a shape. The new shape is a similarOne shape is an enlargement of another. The angles in each shape are the same, and the side lengths are in the same proportion.Β shape.
The increase in size from one shape to another similar shape is called a scale factorThe ratio between corresponding sides in an enlargement..
The position of the enlarged shape is determined by a point, called the centre of enlargementA point which defines the position of an enlarged shape..
Make sure you're confident at working with axes and plotting coordinates and have a good understanding of similar shapes.
Video β Enlargements with fractional scale factors
Watch this video to explore how in order to describe an enlargement, eg from A to B, you need two pieces of information: the centre of enlargement and the scale factor.
The video contains a worked exam-style question.
Katie: Enlargements with fractional scale factors are similar to enlargements with whole scale factors, except that when the scale factor is between 0 and 1, for example, one half, the shape will get smaller after the enlargement, not bigger.
To describe an enlargement from shape A to shape B you need two pieces of information: the centre of enlargement and the scale factor.
The centre of enlargement is found by drawing straight lines through the matching vertices of both shapes and seeing where they meet.
So here, the centre of enlargement is (β3, 0).
Changing this point changes where the enlarged shape B is positioned.
The scale factor is the number that the lengths in the original shape A are multiplied by to give those in the new shape B.
You can calculate the scale factor by dividing the length of one of shape Bβs sides by the corresponding length in shape A.
So here, the scale factor is 2 divided by 4, which equals one half.
Let's draw an enlargement with a scale factor of one third and the centre of enlargement at the origin.
First, count the number of horizontal and vertical squares from the centre of enlargement to each vertex.
Remember, a vertex is a corner where two sides meet.
This vertex is 6 squares to the left and 3 squares down from the origin.
Multiplying both of these distances by the scale factor will give you the position of the corresponding vertex on the enlarged shape.
So the new vertex is 6 times one third, which equals 2, squares to the left of the origin, and 3 times one third, which equals 1, square down from the origin.
Mark this new vertex on your grid.
Repeat this with every vertex, making sure you're counting from the centre of enlargement each time until you have four new vertices.
Join these up with straight lines to give the enlarged shape.
Let's look at an example question.
Shape π΄π΅πΆπ·πΈπΉ is enlarged by a scale factor of one quarter, with a centre of enlargement at (β1, 2)
What are the new coordinates of vertex π΅ after the enlargement?
Pause the video and have a go.
To start, count the number of horizontal and vertical squares from the centre of enlargement to vertex π΅.
That's 6 right and 4 down.
Then, multiply these numbers by the scale factor.
6 times one quarter equals 1.5 and 4 times one quarter equals 1
This means the new vertex will be 1.5 squares to the right of -1 and 1 square down from 2 at the point (0.5, 1).
Remember, enlargements are always specified by the centre of enlargement, which is a pair of coordinates that determines where the enlarged shape ends up, and the scale factor, which is a number, whole or fractional, that tells you what to multiply all the measurements by to give the enlarged shape.
Check your understanding
What is a scale factor?

When a shape is enlarged, the length of each side is multiplied by the same value.
This is called the scale factor.
To make a shape four times bigger, the lengths of all sides are multiplied by four. Since the new shape is similar, all of the angles in the enlarged shape are the same size. The shape has been enlarged by a scale factor of 4.
When given two shapes, calculate the scale factor by dividing the lengths of corresponding sides of each shape.
A scale factor, greater than one, produces a larger shape.
A scale factor between zero and one results in a smaller shape.

Follow the worked example below
GCSE exam-style questions
- Shape πΈπΉπΊπ» is an enlargement of shape π΄π΅πΆπ·.
What is the scale factor of the enlargement?

Scale factor 2

Shape πΈπΉπΊπ» is larger than shape π΄π΅πΆπ·. The scale factor for a larger shape will be greater than one.
Calculate the scale factor by dividing a pair of corresponding sides.
In these shapes π΄π΅ and πΈπΉ are two corresponding horizontal sides.
π΄π΅ has a length of two squares and πΈπΉ has a length of four squares.
Scale factor =\(\frac{ πΈπΉ}{π΄π΅} \) = \(\frac{4}{2} \) = 2.
Therefore, shape πΈπΉπΊπ» is an enlargement of shape π΄π΅πΆπ· by a scale factor of 2.
- Triangle π is an enlargement of triangle π.
What is the scale factor of the enlargement?

Scale factor β

Triangle π is smaller than triangle π. The scale factor for a smaller shape will be between zero and one.
Calculate the scale factor by dividing a pair of corresponding sides.
Triangle π has a horizontal side with length six squares. Triangle π has a corresponding horizontal side with length two squares.
Scale factor = Β²ββ, which can be simplified to β .
Therefore, triangle π is an enlargement of triangle π by a scale factor of β .
Enlarging with a positive scale factor and a centre of enlargement
When using a centre of enlargementA point which defines the position of an enlarged shape., the final position of the enlarged shape can be determined. Shapes can be enlarged on sets of axes.
Check your answer by drawing lines through corresponding pointsWhen a shape is transformed (for example, by translation, rotation, reflection, or enlargement), each point on the original shape matches up with a point on the new shape. These matching points show how the position of the original shape relates to the transformed shape. on the object and image. If done correctly, these will meet at the centre of enlargementA point which defines the position of an enlarged shape..
Watch the example of using a centre of enlargement to enlarge a shape on a set of axes.
Read the steps below to see the full method outlined.
To work out the position of the image after enlargement:
Pick out a vertex on the shape (object).
Count the distance between the centre of enlargement and the vertex. This can be separated into horizontal and vertical displacements.
Multiply these displacements by the scale factor.
Using these values, count from the centre of enlargement to find the position of the corresponding vertex.
Repeat the process for additional vertices.
GCSE exam-style questions
- Enlarge shape π by a scale factor 2.
Use point π with the coordinates of (5, β 5) as the centre of enlargement.
Check the position of the enlargement using paper, a pencil and ruler.
Label your enlargement π.

Shape π has vertices at (1, β 3), (1, 1), ( β 3, 3) and
( β 3, β 3).

The position of each new vertex can be calculated.
For example, the vertex at ( 3, β 4) is two squares to the left and one square above the centre of enlargement.
- Multiply this displacement by the scale factor of 2.
2 Γ 2 = 4 and 1 Γ 2 = 2.
The corresponding point needs to be four squares to the left and two squares above the centre of enlargement.
The corresponding point has the coordinates (1, β 3).
Repeat this for the other three vertices.
Check the position of enlargement by drawing dashed lines through pairs of corresponding points.
If done correctly, the dashed lines will all meet at the centre of enlargement, point π.

- Enlarge triangle πΆ by a scale factor Β½.
Use point π with the coordinates of (2, 5) as the centre of enlargement.
Check the position of the enlargement using paper, a pencil and ruler.

Shape π· has vertices at (3, 3), ( β 2, 3) and ( β 1, β 1).

- Calculate the position of each new vertex.
For example, the vertex at ( β 6, 1) is eight squares to the left and four squares below the centre of enlargement.
- Multiply this displacement, by scale factor of Β½.
Β½ Γ 8 = 4 and Β½ Γ 4 = 2.
The corresponding point needs to be four squares to the left and two squares below the centre of enlargement.
The corresponding point has the coordinates ( β 2, 3).
Repeat for the other two vertices.
Check the position of enlargement by drawing dashed lines through pairs of corresponding points.
If done correctly, the dashed line will all meet at the centre of enlargement, point π.

How do you find the centre of enlargement?
Find the centre of enlargement by using the method for checking the position of an enlarged shape.
The lines which pass through corresponding points on the object and image convergeLines that meet at a point. at the centre of enlargement.
Describe the transformation fully by stating the type of transformation, in this case an enlargement, and calculating the correct scale factor and centre of enlargement.
Follow the worked example below
GCSE exam-style questions
- Rectangle π· is a transformation of rectangle πΆ.
Describe the transformation fully.

Rectangle π· is an enlargement of rectangle πΆ, by a scale factor of 4, with the centre of enlargement at (6, 5).

- Find the centre of enlargement by drawing lines through corresponding points on the object and image.
The lines converge at point π with coordinates (6, 5).
Rectangle π· is larger than rectangle πΆ.
The scale factor for a larger shape will be greater than one.
- Calculate the scale factor by dividing a pair of corresponding sides.
Rectangle πΆ has a vertical side with a length of 1 square.
Rectangle π· has a corresponding vertical side with a length of four squares.
Scale factor = \(\frac{4}{1}\) = 4.

- Shape π΅ is a transformation of shape π΄
Describe the transformation fully.

Shape π΅ is an enlargement of shape π΄ by a scale factor of β , with the centre of enlargement at ( β 6, 3).

- Find the centre of enlargement by drawing lines through corresponding points on the object and image.
The lines converge at point π with the coordinates
(β 6, 3).
Shape π΅ is smaller than shape π΄. The scale factor for a smaller shape will be between zero and one.
- Calculate the scale factor by dividing a pair of corresponding sides.
Shape π΅ has a vertical side with length two squares. Shape π΄ has a corresponding vertical side with length six squares.
Scale factor = Β²ββ, which is simplified to β .

Quiz β Enlargement
Practise what you've learned about enlargement with this quiz.
Now you've revised enlargement, why not look at area of circles and sectors?
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